8x^2+67x-45=0

Solution for 8x^2+67x-45=0 equation:

8x^2+67x-45=0

a = 8; b = 67; c = -45;
Δ = b2-4ac
Δ = 672-4·8·(-45)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5929}=77$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-77}{2*8}=\frac{-144}{16}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+77}{2*8}=\frac{10}{16}
=5/8
$